多维数组转一维数组
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 | var arr = [1,[[4,5,6],2,[[[7,8,9]]],3]];arr = arr.toString().split(",").map(v=>Number(v));
 
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递归算法
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 | var arr = [1,[[4,5,6],2,[[[7,8,9]]],3]];var newArr = [];
 
 function exe(_arr){
 _arr.forEach((v,i)=>{
 if(Array.isArray(v)){
 exe(v);
 }else{
 newArr.push(v);
 }
 })
 }
 
 exe(arr);
 
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求和且查询下标
给定一个整数数组 nums 和一个目标值 target,请你在该数组中找出和为目标值的那 两个 整数,并返回他们的数组下标。
你可以假设每种输入只会对应一个答案。但是,你不能重复利用这个数组中同样的元素。
示例:
给定 nums = [2, 7, 11, 15], target = 9
因为 nums[0] + nums[1] = 2 + 7 = 9
所以返回 [0, 1]
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 | var twoSum = function (nums, target) {var cloneNums = nums.map(function (v) { return v; });
 var indexs = [];
 nums.forEach(function (v, i) {
 cloneNums.forEach(function (_v, _i) {
 if (_v + v === target && i !== _i) {
 indexs = [i, _i];
 }
 });
 });
 return indexs;
 };
 twoSum([3, 3], 6);
 
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千分表示法
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 | var num = 9123123456789.9;var numFloot = num.toString().match(/\.\d+/)[0];
 var intNum:number = Math.floor(num);
 var intNumStr:string = intNum.toString();
 var reverseStr:string = intNumStr.split("").reverse().join("");
 reverseStr = reverseStr.match(/\d{3}/g).map(v=>v+",").join("");
 if(intNumStr.length%3!==0){
 reverseStr+=intNumStr[0];
 }
 var newStr:string|number = reverseStr.split("").reverse().join("") + numFloot;
 newStr = newStr.replace(/^,/,"");
 console.log(newStr);
 
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查询url地址的查询语句
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 | class Param {constructor(key, value) {
 this.key = key;
 this.value = value;
 }
 }
 var result = [];
 var main = function (str) {
 let search = str.match(/\?.+/)[0];
 search = search.replace(/\?/, "");
 let searchs = search.split("&");
 searchs.forEach(v => {
 let _arr = v.split("=");
 result.push(new Param(_arr[0], _arr[1]));
 });
 return result;
 };
 var str = 'http://s.weibo.com/weibo/Aralic?topnav=1&wvr=6&name=jonny&age=34&id=3';
 console.log(main(str));
 
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返回契波那契数列的下标返回值
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 | 
 
 
 
 
 
 
 function getNthFibonacci(count) {
 var fibonacci = [];
 fibonacci[0] = 1;
 fibonacci[1] = 1;
 fibonacci[2] = 2;
 if (count >= 2) {
 for(let i = 3;i<=count;i++){
 fibonacci[i%3] = fibonacci[(i - 1)%3] + fibonacci[(i - 2)%3];
 }
 }
 return fibonacci[count%3];
 }
 
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